Conductors  Art. 310

What is the currentcarrying ampacity of each of nine No. 12 THHN copper conductors installed in ¾in. EMT? (Assume all conductors are currentcarrying.)
a. 17A
b. 21A
c. 25A
d. 28A 
What is the currentcarrying ampacity of each of six No. 14 THHN copper conductors routed through an ambient temperature of 105°F?
a. 17.4A
b. 18.6A
c. 19.8A
d. 21.4A 
What is the currentcarrying ampacity of each of sixteen No. 12 THHN copper conductors, with diversity, located in the same raceway? (Assume only half of the conductors are currentcarrying.)
a. 17A
b. 18A
c. 20A
d. 21A 
What is the currentcarrying ampacity of each of twelve No. 12 THHN copper conductors, if routed in a raceway where there is a total of 16 currentcarrying conductors?
a. 17.2A
b. 18.4A
c. 19.6A
d. 21.2A
answers and discussion

(b), 21A. Cables or raceways enclosing four or more currentcarrying conductors are required to be derated per Sec. 31015(b)(2)(a). The NEC considers all ungrounded (phase) conductors to be currentcarrying. Neutrals for Wye systems are considered currentcarrying if the major portion of the load (more than 50%) consists of harmonic currents [Sec. 31015(b)(4)(c)].
Step 1: Find amperage of each conductor per Table 31016. No. 12 THHN cu. = 30A.
Step 2: Find derating factor per Table 31015(b)(2)(a). 9 conductors requires a 70% derating factor.
Step 3: Recalculate amperage, per Table 31015(b)(2)(a). 30A × 70% = 21A.
Solution: The ampacity of each conductor is 21A.
Stallcup's Code Loop: Secs. 11014(c), 31015(b)(2)(a), and 31015(b)(4)(c), and Tables 31016 and 31015(b)(2)(a).

(a), 17.4A. See explanation for Questions 1 and the following:
Conductors routed through ambient temperatures exceeding 86°F must be derated according to the correction factors listed in Table 31016. The derating factors are listed in the ampacity correction factor at the bottom of Table 31016. Select the derating factors based on the ambient temperature the conductors are exposed to.
Step 1: Find amperage of conductors per Table 31016. No. 14 THHN cu. = 25A
Step 2: Find derating factor for multiple conductors per Table 31015(b)(2)(a). 6 conductors requires an 80% derating factor.
Step 3: Find derating factor for ambient temperature per Table 31016. 105°F requires an 87% derating factor.
Step 4: Recalculate amperage per Tables 31015(b)(2)(a) and 31016. 25A × 80% × 87% = 17.4A.
Solution: The ampacity of each conductor is 17.4A.
Stallcup's Code Loop: Secs. 11014(c), 31015(b)(2)(a), and 31015(b)(4)(c), and Tables 31016 and 31015(b)(2)(a).

(d), 21A. A 50% load diversity can be applied to a conductor ampacity when all the conductors are not loaded at the same time, if allowed by the authority having jurisdiction (AHJ).
Step 1: Find amperage for eight currentcarrying conductors per Table 31016. No. 12 THHN cu. = 30A
Step 2: Find derating factor per Table B31011 in Appendix B. 16 conductors requires a 70% derating factor.
30A × 70% = 21A
Solution: The ampacity of each conductor is 21A, however, only eight at any given time can have this ampacity rating.
Stallcup's Code Loop: Sec. 11014(c), and Tables 31016 and B31011.

(a), 17.2A. You can apply diversity to more than half of the conductors in a raceway or cable if they are limited to a certain calculated value.
Step 1: Apply formula for 12 conductors per Tables B31011 and 31016.
A_{2} = √(0.5 × N/E) × A_{1}, where A_{1}= ampacity of conductor from Table 310316 multiplied by the appropriate adjustment factor in Table B31011
A_{2} = √(0.5 × 16/12) × 30A × 0.7
A_{2} = 17.2ASolution: The ampacity of each conductor is 17.2A.
Stallcup's Code Loop: Sec. 11014(c), and Tables 31016 and B31011.
Stallcup's Code Loops
Each quiz on the 1999 NEC is provided with Stallcup's Code Loops to show the direct correlation with other sections of the NEC. This allows the reader to review other sections of the NEC when determining if the correct answer to a problem is in one or multiple sections of the Code.